Electronic Devices & Circuits

Transistors - Final Exam Preparation

BSc CSE/EEE | Total Marks: 60

Section B: Transistors (BJT)

Q5. Define BJT (Bipolar Junction Transistor) with Symbol.3 Marks

Definition: A BJT is a three-terminal semiconductor device consisting of two PN junctions. It has three regions: Emitter (E), Base (B), and Collector (C). Current flow involves both electrons and holes (bipolar).

A diagram of a full-wave bridge rectifier circuit
Note: Arrow indicates the direction of conventional current flow from emitter.

Q6. BJT Configurations.4 Marks

Three basic configurations based on which terminal is common:

Configuration Input Output Current Gain Voltage Gain Applications
Common Emitter (CE) Base-Emitter Collector-Emitter High (β) High Amplifiers, Switching
Common Base (CB) Emitter-Base Collector-Base Low (<1) High High-frequency amplifiers
Common Collector (CC) Base-Collector Emitter-Collector High Low (<1) Impedance matching, Buffers

Q7. BJT Operating Modes (Junction Biases).4 Marks

BJT has two junctions: Emitter-Base (EB) and Collector-Base (CB). Four operating modes:

Operating Mode EB Junction CB Junction Application
Active/Linear Forward Biased Reverse Biased Amplification
Saturation Forward Biased Forward Biased ON switch (Digital)
Cutoff Reverse Biased Reverse Biased OFF switch (Digital)
Inverse Active Reverse Biased Forward Biased Rarely used
Most Important: Active mode for amplifiers, Saturation & Cutoff for switching circuits.

Q8. Types of Transistors.2 Marks

  • BJT (Bipolar Junction Transistor):
    • NPN Transistor
    • PNP Transistor
  • FET (Field Effect Transistor):
    • JFET (Junction FET) - N-channel, P-channel
    • MOSFET (Metal Oxide Semiconductor FET)
      • Enhancement Mode (E-MOSFET)
      • Depletion Mode (D-MOSFET)

Q9. Characteristics of BJT.3 Marks

Key Characteristics:

  • Current-controlled device: IC depends on IB
  • Low input impedance: Few hundred ohms
  • High output impedance: Several kΩ
  • Temperature sensitive: Performance varies with temperature
  • Power consumption: Higher than FET
  • Switching speed: Moderate (slower than MOSFET)
  • Gain (β): Typically 50-200

Three Main Characteristics:

  • Input Characteristics: IB vs VBE (VCE constant)
  • Output Characteristics: IC vs VCE (IB constant)
  • Transfer Characteristics: IC vs IB (VCE constant)

Q10. Applications of Transistors.2 Marks

  • Amplification: Audio, RF, and power amplifiers
  • Switching: Digital circuits, logic gates
  • Oscillators: Signal generation
  • Voltage Regulation: Power supplies
  • Signal Processing: Modulation, demodulation
  • Motor Control: Speed and direction control

Section C: MOSFET

Q11. Define MOSFET with Symbol.3 Marks

Definition: MOSFET (Metal Oxide Semiconductor Field Effect Transistor) is a voltage-controlled three-terminal device with Gate (G), Drain (D), and Source (S). Current flow is controlled by electric field.

p-n mosfet

Q12. BJT vs MOSFET Comparison.5 Marks

Parameter BJT MOSFET
Control Type Current-controlled (IB controls IC) Voltage-controlled (VGS controls ID)
Terminals Emitter, Base, Collector Source, Gate, Drain
Input Impedance Low (few hundred Ω) Very High (MΩ range)
Current Flow Bipolar (electrons & holes) Unipolar (electrons or holes)
Switching Speed Moderate Fast
Power Consumption Higher Lower
Temperature Stability Less stable More stable
Noise Higher Lower
Size Larger Smaller (IC applications)
Cost Lower Higher
Applications Audio amplifiers, linear circuits Digital circuits, switching, VLSI

Section D: Problem Solving

Q13. Given: α = 0.95, IC = 1.9 mA. Find β, IE, and IB.5 Marks

Given:

  • Amplification factor (α) = 0.95
  • Collector current (IC) = 1.9 mA

Formulas:

α = IC / IE
β = IC / IB
β = α / (1 - α)
IE = IB + IC

Solution:

Step 1: Find Current Gain (β)

β = α / (1 - α) = 0.95 / (1 - 0.95) = 0.95 / 0.05 = 19

Step 2: Find Base Current (IB)

IB = IC / β = 1.9 mA / 19 = 0.1 mA = 100 µA

Step 3: Find Emitter Current (IE)

IE = IB + IC = 0.1 + 1.9 = 2.0 mA
Answer: β = 19, IE = 2.0 mA, IB = 0.1 mA (100 µA)

Q14. Given: β = 50, VCC = 12V, RB = 240 kΩ, RC = 2.2 kΩ (Silicon). Find IB, IC, VCE, VB, VC, VBC. 8 Marks

bjt circuit

Given: β = 50, VCC = 12V, RB = 240 kΩ, RC = 2.2 kΩ

Assume: Silicon transistor ⇒ VBE = 0.7V, VE = 0

Step 1: Base Current (IB)

IB = (VCC − VBE) / RB = (12 − 0.7) / 240kΩ = 47 µA

Step 2: Collector Current (IC)

IC = β × IB = 50 × 47 µA = 2.35 mA

Step 3: Collector Voltage (VC)

VC = VCC − IC × RC = 12 − (2.35 mA × 2.2 kΩ) = 6.83 V

Step 4: Collector-Emitter Voltage (VCE)

VCE = VC − VE = 6.83 − 0 = 6.83 V

Step 5: Base Voltage (VB)

VB = VBE + VE = 0.7 V

Step 6: Base-Collector Voltage (VBC)

VBC = VB − VC = 0.7 − 6.83 = −6.13 V
Final Answers:
IB = 47 µA, IC = 2.35 mA, VC = 6.83 V,
VCE = 6.83 V, VB = 0.7 V, VBC = −6.13 V
(VBC negative ⇒ transistor operates in active region)

Q15. Additional Important Formulas.2 Marks

Current Relations:

IE = IB + IC
IC = β × IB
IC = α × IE
α = β / (β + 1)
β = α / (1 - α)

Typical Values:

  • α: 0.95 to 0.99
  • β: 20 to 200
  • VBE (Silicon): 0.7V
  • VBE (Germanium): 0.3V

Section E: Additional Topics

Q16. Transistor as an Amplifier.3 Marks

In active region, small changes in base current cause large changes in collector current.

  • Voltage Gain (AV): AV = Vout / Vin = -β × (RC / Rin)
  • Current Gain (AI): AI = IC / IB = β
  • Power Gain (AP): AP = AV × AI

CE configuration provides both voltage and current gain, making it most popular for amplification.

Q17. Transistor as a Switch.3 Marks

Transistor operates between cutoff (OFF) and saturation (ON):

  • Cutoff Mode (OFF): IB = 0, IC ≈ 0, VCE ≈ VCC (Open switch)
  • Saturation Mode (ON): IB is large, IC = VCC/RC, VCE ≈ 0.2V (Closed switch)

Applications: Digital logic gates, relay drivers, LED drivers, motor control

Q18. Biasing Techniques.2 Marks

  • Fixed Bias: Simple but temperature unstable
  • Voltage Divider Bias: Most stable, widely used
  • Emitter Bias: Good stability with negative supply
  • Collector Feedback Bias: Moderate stability

Q20. Advantages and Disadvantages.3 Marks

BJT Advantages:

  • High current handling capacity
  • Better for analog/linear applications
  • Lower cost
  • Higher transconductance

BJT Disadvantages:

  • Lower input impedance
  • Temperature sensitive
  • Slower switching speed
  • Requires continuous base current

Most important Questions from teacher in the class

A diagram of a full-wave bridge rectifier circuit
A diagram of a full-wave bridge rectifier circuit
A diagram of a full-wave bridge rectifier circuit
A diagram of a full-wave bridge rectifier circuit

Exam Preparation Complete!

Total Questions: 20 | Total Marks: 60

Study Focus: Diode characteristics, BJT configurations, Operating modes, Problem solving
Good Luck for Your Final Exam!